What is the solution for x^2y^'-ysqrt(x)=0 ?

The solution for x^2y^'-ysqrt(x)=0 is y=e^{-2/(sqrt(x))+c_{1}}

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x^2y^'-ysqrt(x)=0

x^{2} y^{^{'}} - y x = 0

y = e^{- \frac{2}{x} + c_{1}}

Solution steps

x^{2} y^{'} (x) - y x = 0

Solve separable ODE:

y = e^{- \frac{2}{x} + c_{1}}

y = e^{- \frac{2}{x} + c_{1}}

\frac{d}{d x} (6 x^{4} - 2 x + 7)

\frac{1}{( s - 1 ) ^{2}}

\int_{0}^{1} k x d x

y = cos (x^{2})

\frac{d}{d x} (\frac{- 5 x - 9}{2 x + 8})

What is the solution for x^2y^'-ysqrt(x)=0 ?
The solution for x^2y^'-ysqrt(x)=0 is y=e^{-2/(sqrt(x))+c_{1}}