What is the derivative of ln(x-a) ?

The derivative of ln(x-a) is 1/(x-a)

What is the first derivative of ln(x-a) ?

The first derivative of ln(x-a) is 1/(x-a)

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\frac{d}{d x} (ln (x - a))

\frac{1}{x - a}

Solution steps

\frac{d}{d x} (ln (x - a))

Apply the chain rule:

\frac{1}{x - a} \frac{d}{d x} (x - a)

= \frac{1}{x - a} \frac{d}{d x} (x - a)

\frac{d}{d x} (x - a) = 1

= \frac{1}{x - a} \cdot 1

Simplify

= \frac{1}{x - a}

\frac{\partial}{\partial x} (\frac{( u - v )}{u + v})

\int 1 + (x)^{2} d x

\int (x + 2) (x - 6) d x

9 y^{^{''}} - 6 y^{^{'}} + 15 y = 0

\int sin (10 x) cos (7 x) d x

What is the derivative of ln(x-a) ?
The derivative of ln(x-a) is 1/(x-a)
What is the first derivative of ln(x-a) ?
The first derivative of ln(x-a) is 1/(x-a)