What is (\partial)/(\partial x)(x^3yz^2) ?

The answer to (\partial)/(\partial x)(x^3yz^2) is 3x^2yz^2

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(\partial)/(\partial x)(x^3yz^2)

\frac{\partial}{\partial x} (x^{3} y z^{2})

3 x^{2} y z^{2}

Solution steps

\frac{\partial}{\partial x} (x^{3} y z^{2})

Treat

y, z

as constants

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= y z^{2} \frac{\partial}{\partial x} (x^{3})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= y z^{2} \cdot 3 x^{3 - 1}

Simplify

= 3 x^{2} y z^{2}

ln ∣ ln (x) ∣

\frac{d y}{d t} + \frac{1}{20} y = \frac{3}{2}, y (0) = 0

\frac{d}{d t} (t cos (t) - sin (t))

(t^{3})^{^{'}}

\frac{d}{d x} ((\frac{x ^{3} - 1}{x ^{3} + 1})^{8})

What is (\partial)/(\partial x)(x^3yz^2) ?
The answer to (\partial)/(\partial x)(x^3yz^2) is 3x^2yz^2