What is the derivative of 1/35 x^5+1/4 x^4+x+1 ?

The derivative of 1/35 x^5+1/4 x^4+x+1 is (x^4)/7+x^3+1

What is the first derivative of 1/35 x^5+1/4 x^4+x+1 ?

The first derivative of 1/35 x^5+1/4 x^4+x+1 is (x^4)/7+x^3+1

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\frac{d}{d x} (\frac{1}{35} x^{5} + \frac{1}{4} x^{4} + x + 1)

\frac{x ^{4}}{7} + x^{3} + 1

Solution steps

\frac{d}{d x} (\frac{1}{35} x^{5} + \frac{1}{4} x^{4} + x + 1)

Simplify

\frac{1}{35} x^{5} + \frac{1}{4} x^{4} + x + 1 : \frac{x ^{5}}{35} + \frac{x ^{4}}{4} + x + 1

= \frac{d}{d x} (\frac{x ^{5}}{35} + \frac{x ^{4}}{4} + x + 1)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (\frac{x ^{5}}{35}) + \frac{d}{d x} (\frac{x ^{4}}{4}) + \frac{d x}{d x} + \frac{d}{d x} (1)

\frac{d}{d x} (\frac{x ^{5}}{35}) = \frac{x ^{4}}{7}

\frac{d}{d x} (\frac{x ^{4}}{4}) = x^{3}

\frac{d x}{d x} = 1

\frac{d}{d x} (1) = 0

= \frac{x ^{4}}{7} + x^{3} + 1 + 0

Simplify

= \frac{x ^{4}}{7} + x^{3} + 1

f (x) = 8 x 16 + 0.5 x

\int_{2}^{5} \frac{x}{3} d x

n = 0 \sum \infty (1 + \frac{1}{n})^{n}

8 cot (\frac{π x}{16})

\frac{d}{d x} (3 sec (5 x))

What is the derivative of 1/35 x^5+1/4 x^4+x+1 ?
The derivative of 1/35 x^5+1/4 x^4+x+1 is (x^4)/7+x^3+1
What is the first derivative of 1/35 x^5+1/4 x^4+x+1 ?
The first derivative of 1/35 x^5+1/4 x^4+x+1 is (x^4)/7+x^3+1