What is the sum from n=0 to infinity of (1+1/n)^n ?

The sum from n=0 to infinity of (1+1/n)^n is diverges

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sum from n=0 to infinity of (1+1/n)^n

n = 0 \sum \infty (1 + \frac{1}{n})^{n}

diverges

Solution steps

n = 1 \sum \infty (1 + \frac{1}{n})^{n}

Apply Series Divergence Test:

diverges

= diverges

8 cot (\frac{π x}{16})

\frac{d}{d x} (3 sec (5 x))

\frac{d}{d x} (7 arctan (x))

x \to 1 lim (4 x - x^{2})

y = x^{3} - 3 x^{2} + 2, (3, 2)

What is the sum from n=0 to infinity of (1+1/n)^n ?
The sum from n=0 to infinity of (1+1/n)^n is diverges