What is the solution for xdy-(sqrt(x^2-y^2)+y)*dx=0 ?

The solution for xdy-(sqrt(x^2-y^2)+y)*dx=0 is y=sin(ln(x)+c_{1})x

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xdy-(sqrt(x^2-y^2)+y)*dx=0

x d y - (x^{2} - y^{2} + y) \cdot d x = 0

y = sin (ln (x) + c_{1}) x

Solution steps

x d y - (x^{2} - y^{2} + y) \cdot d x = 0

Solve using substitution:

y = sin (ln (x) + c_{1}) x

y = sin (ln (x) + c_{1}) x

y = \frac{x + 2}{x - 2}, (3, 5)

\int \frac{8 x ^{3} + 3}{( x ^{2} + 2 ) ^{2}} d x

\frac{\partial}{\partial x} (sin^{2} (m x + n y))

\int 2^{s i n^{2} (\frac{1}{3} x)} sin (\frac{2}{3} x) d x

\frac{1}{x ^{2}}, - 1

What is the solution for xdy-(sqrt(x^2-y^2)+y)*dx=0 ?
The solution for xdy-(sqrt(x^2-y^2)+y)*dx=0 is y=sin(ln(x)+c_{1})x