What is the solution for y^{''}+y=3x^2 ?

The solution for y^{''}+y=3x^2 is y=c_{1}cos(x)+c_{2}sin(x)+3x^2-6

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y^{''}+y=3x^2

y^{^{''}} + y = 3 x^{2}

y = c_{1} cos (x) + c_{2} sin (x) + 3 x^{2} - 6

Solution steps

y^{''} (x) + y = 3 x^{2}

Solve linear ODE:

y = c_{1} cos (x) + c_{2} sin (x) + 3 x^{2} - 6

y = c_{1} cos (x) + c_{2} sin (x) + 3 x^{2} - 6

\int_{0}^{\frac{π}{8}} cos (4 x) d x

\frac{d}{d x} (5 x^{4} - 3 x^{2} + \frac{1}{x})

x \to 4 lim (∣ x + 4 ∣)

x^{2} y^{^{'}} + x y = 4

\frac{\partial}{\partial x} (f (x) (x f (x) (x f (x))))

What is the solution for y^{''}+y=3x^2 ?
The solution for y^{''}+y=3x^2 is y=c_{1}cos(x)+c_{2}sin(x)+3x^2-6