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Popular >

x^2y^'+xy=4

Solution

x^{2} y^{^{'}} + x y = 4

Solution

y = \frac{4 ln ( x )}{x} + \frac{c _{1}}{x}

Solution steps

x^{2} y^{'} (x) + x y = 4

Solve linear ODE:

y = \frac{4 ln ( x )}{x} + \frac{c _{1}}{x}

y = \frac{4 ln ( x )}{x} + \frac{c _{1}}{x}

Graph

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Frequently Asked Questions (FAQ)

What is the solution for x^2y^'+xy=4 ?
The solution for x^2y^'+xy=4 is y=(4ln(x))/x+(c_{1})/x