What is the derivative of (x^3+x)^6 ?

The derivative of (x^3+x)^6 is 6(x^3+x)^5(3x^2+1)

What is the first derivative of (x^3+x)^6 ?

The first derivative of (x^3+x)^6 is 6(x^3+x)^5(3x^2+1)

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derivative of

(x^{3} + x)^{6}

6 (x^{3} + x)^{5} (3 x^{2} + 1)

Solution steps

\frac{d}{d x} ((x^{3} + x)^{6})

Apply the chain rule:

6 (x^{3} + x)^{5} \frac{d}{d x} (x^{3} + x)

= 6 (x^{3} + x)^{5} \frac{d}{d x} (x^{3} + x)

\frac{d}{d x} (x^{3} + x) = 3 x^{2} + 1

= 6 (x^{3} + x)^{5} (3 x^{2} + 1)

\frac{d}{d x} (f (x) \cdot g (x))

\int \frac{3}{5} sec (x) tan (x) d x

(1 + 2 x)^{2} (1 - x)^{50} + 3 x^{3} - 7 e

\frac{\partial}{\partial y} (1 - x^{2} y)

\int \frac{x}{( 1 + x )} d x

What is the derivative of (x^3+x)^6 ?
The derivative of (x^3+x)^6 is 6(x^3+x)^5(3x^2+1)
What is the first derivative of (x^3+x)^6 ?
The first derivative of (x^3+x)^6 is 6(x^3+x)^5(3x^2+1)