What is (\partial)/(\partial x)(e^{2x}cos(6y)) ?

The answer to (\partial)/(\partial x)(e^{2x}cos(6y)) is cos(6y)e^{2x}*2

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(\partial)/(\partial x)(e^{2x}cos(6y))

\frac{\partial}{\partial x} (e^{2 x} cos (6 y))

cos (6 y) e^{2 x} \cdot 2

Solution steps

\frac{\partial}{\partial x} (e^{2 x} cos (6 y))

Treat

y

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= cos (6 y) \frac{\partial}{\partial x} (e^{2 x})

Apply the chain rule:

e^{2 x} \frac{\partial}{\partial x} (2 x)

= e^{2 x} \frac{\partial}{\partial x} (2 x)

\frac{\partial}{\partial x} (2 x) = 2

= cos (6 y) e^{2 x} \cdot 2

\frac{d}{d x} (sin^{3} (cos (x)))

\frac{d ^{2} y}{d x ^{2}} = \frac{( 6 x ^{5} )}{5} - 3 x

n \to \infty lim (n 0.25 - \frac{n}{n})

y = \frac{x ^{2} + 1}{x + 1}

\int_{1}^{6} w w + 3 d w

What is (\partial)/(\partial x)(e^{2x}cos(6y)) ?
The answer to (\partial)/(\partial x)(e^{2x}cos(6y)) is cos(6y)e^{2x}*2