What is the derivative of f(x)=2x^2+5x ?

The derivative of f(x)=2x^2+5x is 4x+5

What is the first derivative of f(x)=2x^2+5x ?

The first derivative of f(x)=2x^2+5x is 4x+5

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derivative of

f (x) = 2 x^{2} + 5 x

4 x + 5

Solution steps

\frac{d}{d x} (2 x^{2} + 5 x)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (2 x^{2}) + \frac{d}{d x} (5 x)

\frac{d}{d x} (2 x^{2}) = 4 x

\frac{d}{d x} (5 x) = 5

= 4 x + 5

\int 2 t d t

- x^{2} + 4 x + 1, x + 1

\int \frac{( y - 3 )}{y} d y

\frac{1}{x ^{2}}

(t + 3) (2 t - 1)^{2}

What is the derivative of f(x)=2x^2+5x ?
The derivative of f(x)=2x^2+5x is 4x+5
What is the first derivative of f(x)=2x^2+5x ?
The first derivative of f(x)=2x^2+5x is 4x+5