What is (\partial)/(\partial x)(2y^2x) ?

The answer to (\partial)/(\partial x)(2y^2x) is 2y^2

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(\partial)/(\partial x)(2y^2x)

\frac{\partial}{\partial x} (2 y^{2} x)

2 y^{2}

Solution steps

\frac{\partial}{\partial x} (2 y^{2} x)

Treat

y

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 2 y^{2} \frac{\partial}{\partial x} (x)

Apply the common derivative:

\frac{\partial}{\partial x} (x) = 1

= 2 y^{2} \cdot 1

Simplify

= 2 y^{2}

N + 1 X

y^{^{''}} + 16 y = e^{2 t} tan (4 t)

x \to 2 lim ((x^{2} + 8) (2 x - 4))

y \to - \infty lim (\frac{2 - y}{7 + 6 y ^{2}})

\frac{\partial}{\partial y} (26 - x^{2} - 4 y^{2})

What is (\partial)/(\partial x)(2y^2x) ?
The answer to (\partial)/(\partial x)(2y^2x) is 2y^2