What is the derivative of 9x^2+6x-2 ?

The derivative of 9x^2+6x-2 is 18x+6

What is the first derivative of 9x^2+6x-2 ?

The first derivative of 9x^2+6x-2 is 18x+6

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\frac{d}{d x} (9 x^{2} + 6 x - 2)

18 x + 6

Solution steps

\frac{d}{d x} (9 x^{2} + 6 x - 2)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (9 x^{2}) + \frac{d}{d x} (6 x) - \frac{d}{d x} (2)

\frac{d}{d x} (9 x^{2}) = 18 x

\frac{d}{d x} (6 x) = 6

\frac{d}{d x} (2) = 0

= 18 x + 6 - 0

Simplify

= 18 x + 6

\int_{0}^{\infty} \frac{x}{x ^{4} + 1} d x

x \to 1 lim (\frac{x + 2}{1 - x})

\frac{d}{d x} (x^{10} e^{x} + 10)

f (x) = 7 x

\frac{d}{d θ} (cos (θ) i + 3 sin (θ) j)

What is the derivative of 9x^2+6x-2 ?
The derivative of 9x^2+6x-2 is 18x+6
What is the first derivative of 9x^2+6x-2 ?
The first derivative of 9x^2+6x-2 is 18x+6