What is the derivative of 2x^2-4x ?

The derivative of 2x^2-4x is 4x-4

What is the first derivative of 2x^2-4x ?

The first derivative of 2x^2-4x is 4x-4

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derivative of

2 x^{2} - 4 x

4 x - 4

Solution steps

\frac{d}{d x} (2 x^{2} - 4 x)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (2 x^{2}) - \frac{d}{d x} (4 x)

\frac{d}{d x} (2 x^{2}) = 4 x

\frac{d}{d x} (4 x) = 4

= 4 x - 4

\frac{\partial}{\partial z} (- z)

\int \frac{1}{( x - 2 ) ( x - 3 )} d x

y^{^{'''}} + 3 y^{^{''}} - 16 y^{^{'}} - 48 y = 0

\int_{- 3}^{3} \frac{18}{x ^{2} - 6 x - 72} d x

\frac{\partial}{\partial y} (\frac{2 x}{( 2 x + 3 y ) ^{2}})

What is the derivative of 2x^2-4x ?
The derivative of 2x^2-4x is 4x-4
What is the first derivative of 2x^2-4x ?
The first derivative of 2x^2-4x is 4x-4