What is the limit as x approaches 0+of (ln(x))^2 ?

The limit as x approaches 0+of (ln(x))^2 is infinity

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limit as x approaches 0+of (ln(x))^2

x \to 0 + lim ((ln (x))^{2})

\infty

Solution steps

x \to 0 + lim ((ln (x))^{2})

x \to a lim [f (x)]^{b} = [x \to a lim f (x)]^{b}

With the exception of indeterminate form

= (x \to 0 + lim (ln (x)))^{2}

Apply the common limit:

x \to 0 + lim (ln (x)) = - \infty

= (- \infty)^{2}

Apply Infinity Property:

(- \infty)^{n} = \infty, n

is even

= \infty

sec^{2} (x) + tan^{2} (x)

f (x) = 15 x - 1.86 x^{2}, at x = a

\frac{d}{d x} (7^{x^{2}})

\int - 3 x^{2} - 20 x + 2000 d x

(1 + x^{2}) \frac{d y}{d x} - \frac{4 x ^{3} y}{1 - x ^{2}} = 1

What is the limit as x approaches 0+of (ln(x))^2 ?
The limit as x approaches 0+of (ln(x))^2 is infinity