What is the integral from 0 to 4 of te^{-t} ?

The integral from 0 to 4 of te^{-t} is -5/(e^4)+1

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integral from 0 to 4 of te^{-t}

\int_{0}^{4} t e^{- t} d t

- \frac{5}{e ^{4}} + 1

Decimal

0.90842 \dots

Solution steps

\int_{0}^{4} t e^{- t} d t

Apply Integration By Parts

: [- e^{- t} t - \int - e^{- t} d t]_{0}^{4}

= [- e^{- t} t - \int - e^{- t} d t]_{0}^{4}

\int - e^{- t} d t = e^{- t}

= [- e^{- t} t - e^{- t}]_{0}^{4}

Compute the boundaries:

- \frac{5}{e ^{4}} + 1

= - \frac{5}{e ^{4}} + 1

\frac{400}{25 s ( s ^{2} + 200 )}

y = tan (x), (\frac{π}{4}, 1)

\int_{8}^{12} \frac{2}{x ^{3}} d x

\int (x ln (x))^{2} d x

\frac{\partial}{\partial x} (y e^{y})

What is the integral from 0 to 4 of te^{-t} ?
The integral from 0 to 4 of te^{-t} is -5/(e^4)+1