What is the derivative of (64x-4)(8x^2-x+5) ?

The derivative of (64x-4)(8x^2-x+5) is 1536x^2-192x+324

What is the first derivative of (64x-4)(8x^2-x+5) ?

The first derivative of (64x-4)(8x^2-x+5) is 1536x^2-192x+324

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

derivative of

(64 x - 4) (8 x^{2} - x + 5)

1536 x^{2} - 192 x + 324

Solution steps

\frac{d}{d x} ((64 x - 4) (8 x^{2} - x + 5))

Apply the Product Rule:

(f \cdot g)^{'} = f^{'} \cdot g + f \cdot g^{'}

f = 64 x - 4, g = 8 x^{2} - x + 5

= \frac{d}{d x} (64 x - 4) (8 x^{2} - x + 5) + \frac{d}{d x} (8 x^{2} - x + 5) (64 x - 4)

\frac{d}{d x} (64 x - 4) = 64

\frac{d}{d x} (8 x^{2} - x + 5) = 16 x - 1

= 64 (8 x^{2} - x + 5) + (16 x - 1) (64 x - 4)

Simplify

64 (8 x^{2} - x + 5) + (16 x - 1) (64 x - 4) : 1536 x^{2} - 192 x + 324

= 1536 x^{2} - 192 x + 324

\frac{d}{d t} (t e^{- t})

\int (3 - sin (x)) d x

\int_{0}^{7} x e^{- 2 x} d x

\frac{d}{d x} (64 sin (2 x))

\frac{d}{d x} (sec^{9} (2^{x}))

What is the derivative of (64x-4)(8x^2-x+5) ?
The derivative of (64x-4)(8x^2-x+5) is 1536x^2-192x+324
What is the first derivative of (64x-4)(8x^2-x+5) ?
The first derivative of (64x-4)(8x^2-x+5) is 1536x^2-192x+324