What is the derivative of sin(x^2+e^x) ?

The derivative of sin(x^2+e^x) is cos(x^2+e^x)(2x+e^x)

What is the first derivative of sin(x^2+e^x) ?

The first derivative of sin(x^2+e^x) is cos(x^2+e^x)(2x+e^x)

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\frac{d}{d x} (sin (x^{2} + e^{x}))

cos (x^{2} + e^{x}) (2 x + e^{x})

Solution steps

\frac{d}{d x} (sin (x^{2} + e^{x}))

Apply the chain rule:

cos (x^{2} + e^{x}) \frac{d}{d x} (x^{2} + e^{x})

= cos (x^{2} + e^{x}) \frac{d}{d x} (x^{2} + e^{x})

\frac{d}{d x} (x^{2} + e^{x}) = 2 x + e^{x}

= cos (x^{2} + e^{x}) (2 x + e^{x})

f (x) = \frac{5 x ^{4} - 3 x ^{3}}{x ^{5}}

(\frac{x - 1}{x + 1})^{^{'}}

\int_{0}^{π} 3 sin (x) d x

\int_{1}^{6} π (x - 1) d x

\frac{d r}{d t} = 6 (t + 1)^{\frac{1}{2}}, r (0) = 0

What is the derivative of sin(x^2+e^x) ?
The derivative of sin(x^2+e^x) is cos(x^2+e^x)(2x+e^x)
What is the first derivative of sin(x^2+e^x) ?
The first derivative of sin(x^2+e^x) is cos(x^2+e^x)(2x+e^x)