What is the sum from n=1 to infinity of (n!)/(e^n) ?

The sum from n=1 to infinity of (n!)/(e^n) is diverges

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sum from n=1 to infinity of (n!)/(e^n)

n = 1 \sum \infty \frac{n !}{e ^{n}}

diverges

Solution steps

n = 1 \sum \infty \frac{n !}{e ^{n}}

Apply Series Ratio Test:

diverges

= diverges

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What is the sum from n=1 to infinity of (n!)/(e^n) ?
The sum from n=1 to infinity of (n!)/(e^n) is diverges