What is (\partial)/(\partial x)(tan(x^2+y)) ?

The answer to (\partial)/(\partial x)(tan(x^2+y)) is sec^2(x^2+y)*2x

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(\partial)/(\partial x)(tan(x^2+y))

\frac{\partial}{\partial x} (tan (x^{2} + y))

sec^{2} (x^{2} + y) \cdot 2 x

Solution steps

\frac{\partial}{\partial x} (tan (x^{2} + y))

Treat

y

as a constant

Apply the chain rule:

sec^{2} (x^{2} + y) \frac{\partial}{\partial x} (x^{2} + y)

= sec^{2} (x^{2} + y) \frac{\partial}{\partial x} (x^{2} + y)

\frac{\partial}{\partial x} (x^{2} + y) = 2 x

= sec^{2} (x^{2} + y) \cdot 2 x

y = sin (x), y = cos (x), x = \frac{5 π}{4}, x = 2 π

y = \frac{2 x}{x + 2}, (2, 1)

\frac{d}{d x} ((4^{x})^{9})

x \to \infty + lim (\frac{1}{0})

d x + (x - ey) d y = 0

What is (\partial)/(\partial x)(tan(x^2+y)) ?
The answer to (\partial)/(\partial x)(tan(x^2+y)) is sec^2(x^2+y)*2x