What is area y=sin(x),y=cos(x),x=(5pi)/4 ,x=2pi ?

The answer to area y=sin(x),y=cos(x),x=(5pi)/4 ,x=2pi is 1+sqrt(2)

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area y=sin(x),y=cos(x),x=(5pi)/4 ,x=2pi

area

y = sin (x), y = cos (x), x = \frac{5 π}{4}, x = 2 π

1 + 2

Decimal Notation

2.41421 \dots

Solution steps

Apply the area formula:

\int_{\frac{5 π}{4}}^{2 π} ∣ sin (x) - cos (x) ∣ d x

Solve

\int_{\frac{5 π}{4}}^{2 π} ∣ sin (x) - cos (x) ∣ d x : 1 + 2

The area is:

= 1 + 2

y = \frac{2 x}{x + 2}, (2, 1)

\frac{d}{d x} ((4^{x})^{9})

x \to \infty + lim (\frac{1}{0})

d x + (x - ey) d y = 0

3 x^{4} + 3 x

What is area y=sin(x),y=cos(x),x=(5pi)/4 ,x=2pi ?
The answer to area y=sin(x),y=cos(x),x=(5pi)/4 ,x=2pi is 1+sqrt(2)