What is the derivative of 3x^4+3x ?

The derivative of 3x^4+3x is 12x^3+3

What is the first derivative of 3x^4+3x ?

The first derivative of 3x^4+3x is 12x^3+3

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derivative of

3 x^{4} + 3 x

12 x^{3} + 3

Solution steps

\frac{d}{d x} (3 x^{4} + 3 x)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (3 x^{4}) + \frac{d}{d x} (3 x)

\frac{d}{d x} (3 x^{4}) = 12 x^{3}

\frac{d}{d x} (3 x) = 3

= 12 x^{3} + 3

x \to 2 lim (x^{2} - 2 x - 2)

\frac{d y}{d t} = t^{3} + 174

7 u + 2 u

\int \frac{x ^{2}}{x ^{2} - 1} d x

g (x) = 2 (4 - 7 x)^{4}

What is the derivative of 3x^4+3x ?
The derivative of 3x^4+3x is 12x^3+3
What is the first derivative of 3x^4+3x ?
The first derivative of 3x^4+3x is 12x^3+3