What is (\partial)/(\partial x)(e^{-2x}cos(6y)) ?

The answer to (\partial)/(\partial x)(e^{-2x}cos(6y)) is -2e^{-2x}cos(6y)

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(\partial)/(\partial x)(e^{-2x}cos(6y))

\frac{\partial}{\partial x} (e^{- 2 x} cos (6 y))

- 2 e^{- 2 x} cos (6 y)

Solution steps

\frac{\partial}{\partial x} (e^{- 2 x} cos (6 y))

Treat

y

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= cos (6 y) \frac{\partial}{\partial x} (e^{- 2 x})

Apply the chain rule:

e^{- 2 x} \frac{\partial}{\partial x} (- 2 x)

= e^{- 2 x} \frac{\partial}{\partial x} (- 2 x)

\frac{\partial}{\partial x} (- 2 x) = - 2

= cos (6 y) e^{- 2 x} (- 2)

Simplify

= - 2 e^{- 2 x} cos (6 y)

x \to x lim (25)

\int \frac{4 x ^{3}}{x ^{2} + 9} d x

f (x) = 2 x^{2} - 2 x - 2, at x = 1

f^{^{'}} (x) = cos (cos (x))

n = 0 \sum \infty n + 1 (\frac{1}{9})^{n}

What is (\partial)/(\partial x)(e^{-2x}cos(6y)) ?
The answer to (\partial)/(\partial x)(e^{-2x}cos(6y)) is -2e^{-2x}cos(6y)