What is the tangent of y=cos(x),\at x= pi/2 ?

The tangent of y=cos(x),\at x= pi/2 is y=-x+pi/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

tangent of y=cos(x),\at x= pi/2

tangent of

y = cos (x), at x = \frac{π}{2}

y = - x + \frac{π}{2}

Solution steps

Find the tangent point:

(\frac{π}{2}, 0)

Find the slope of

y = cos (x) : \frac{d y}{d x} = - sin (x)

Compute the slope of

y = cos (x)

x = \frac{π}{2} : m = - 1

Find the line with slope m=

- 1

and passing through

(\frac{π}{2}, 0) : y = - x + \frac{π}{2}

y = - x + \frac{π}{2}

\frac{d}{d x} (x + x x)

\frac{d}{d x} (x^{3} + 3^{x})

\int sin (x) 2 x d x

x \to \infty lim (\frac{( x ^{2} )}{e ^{x^{2}}})

n = 0 \sum \infty \frac{1 ^{n}}{3 ^{n}}

What is the tangent of y=cos(x),\at x= pi/2 ?
The tangent of y=cos(x),\at x= pi/2 is y=-x+pi/2