What is the derivative of (x+2)(x-5)(x-1) ?

The derivative of (x+2)(x-5)(x-1) is 3x^2-8x-7

What is the first derivative of (x+2)(x-5)(x-1) ?

The first derivative of (x+2)(x-5)(x-1) is 3x^2-8x-7

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derivative of

(x + 2) (x - 5) (x - 1)

3 x^{2} - 8 x - 7

Solution steps

\frac{d}{d x} ((x + 2) (x - 5) (x - 1))

Apply the Product Rule:

(f \cdot g)^{'} = f^{'} \cdot g + f \cdot g^{'}

f = x + 2, g = (x - 5) (x - 1)

= \frac{d}{d x} (x + 2) (x - 5) (x - 1) + \frac{d}{d x} ((x - 5) (x - 1)) (x + 2)

\frac{d}{d x} (x + 2) = 1

\frac{d}{d x} ((x - 5) (x - 1)) = 2 x - 6

= 1 \cdot (x - 5) (x - 1) + (2 x - 6) (x + 2)

Simplify

1 \cdot (x - 5) (x - 1) + (2 x - 6) (x + 2) : 3 x^{2} - 8 x - 7

= 3 x^{2} - 8 x - 7

x \to 0 lim (3 (h + 2 x) 2)

\int \frac{5}{x + 2} d x

\frac{d}{d x} (4 x^{2} (3 x - 1)^{3})

y = 7 x^{2} - x^{3}, (1, 6)

\int e^{x z} d y

What is the derivative of (x+2)(x-5)(x-1) ?
The derivative of (x+2)(x-5)(x-1) is 3x^2-8x-7
What is the first derivative of (x+2)(x-5)(x-1) ?
The first derivative of (x+2)(x-5)(x-1) is 3x^2-8x-7