What is the derivative of 4x^2(3x-1^3) ?

The derivative of 4x^2(3x-1^3) is 4(2x(3x-1)^3+9(3x-1)^2x^2)

What is the first derivative of 4x^2(3x-1^3) ?

The first derivative of 4x^2(3x-1^3) is 4(2x(3x-1)^3+9(3x-1)^2x^2)

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\frac{d}{d x} (4 x^{2} (3 x - 1)^{3})

4 (2 x (3 x - 1)^{3} + 9 (3 x - 1)^{2} x^{2})

Solution steps

\frac{d}{d x} (4 x^{2} (3 x - 1)^{3})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 4 \frac{d}{d x} (x^{2} (3 x - 1)^{3})

Apply the Product Rule:

(f \cdot g)^{'} = f^{'} \cdot g + f \cdot g^{'}

f = x^{2}, g = (3 x - 1)^{3}

= 4 (\frac{d}{d x} (x^{2}) (3 x - 1)^{3} + \frac{d}{d x} ((3 x - 1)^{3}) x^{2})

\frac{d}{d x} (x^{2}) = 2 x

\frac{d}{d x} ((3 x - 1)^{3}) = 9 (3 x - 1)^{2}

= 4 (2 x (3 x - 1)^{3} + 9 (3 x - 1)^{2} x^{2})

y = 7 x^{2} - x^{3}, (1, 6)

\int e^{x z} d y

\frac{d}{d x} ((x^{2} - 2)^{3})

\int 5 x^{- 1} d x

What is the derivative of 4x^2(3x-1^3) ?
The derivative of 4x^2(3x-1^3) is 4(2x(3x-1)^3+9(3x-1)^2x^2)
What is the first derivative of 4x^2(3x-1^3) ?
The first derivative of 4x^2(3x-1^3) is 4(2x(3x-1)^3+9(3x-1)^2x^2)