What is laplacetransform 10+t^2 ?

The answer to laplacetransform 10+t^2 is (10)/s+2/(s^3)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

laplacetransform 10+t^2

laplace transform

10 + t^{2}

\frac{10}{s} + \frac{2}{s ^{3}}

Solution steps

L {10 + t^{2}}

Use the linearity property of Laplace Transform:

For functions

f (t), g (t)

and constants

a, b : L {a \cdot f (t) + b \cdot g (t)} = a \cdot L {f (t)} + b \cdot L {g (t)}

= L {10} + L {t^{2}}

L {10} : \frac{10}{s}

L {t^{2}} : \frac{2}{s ^{3}}

= \frac{10}{s} + \frac{2}{s ^{3}}

\frac{\partial}{\partial z} (- y e^{z^{3} + z^{2} + 1})

\int_{0}^{π} sin^{2} (7 x) d x

n = 1 \sum \infty \frac{3 ^{n}}{n ^{2}}

\int - sec^{2} (x) d x

\int \frac{t ^{2} + 1}{t} d t

What is laplacetransform 10+t^2 ?
The answer to laplacetransform 10+t^2 is (10)/s+2/(s^3)