What is the integral of-sec^2(x) ?

The integral of-sec^2(x) is -tan(x)+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral of-sec^2(x)

\int - sec^{2} (x) d x

- tan (x) + C

Solution steps

\int - sec^{2} (x) d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= - \int sec^{2} (x) d x

Use the common integral:

\int sec^{2} (x) d x = tan (x)

= - tan (x)

Add a constant to the solution

= - tan (x) + C

\int \frac{t ^{2} + 1}{t} d t

\int \frac{3}{x ^{\frac{1}{2}}} d x

n = 0 \sum \infty 2

\int_{0}^{2} \frac{8 t}{( t - 3 ) ^{2}} d t

\frac{d}{d x} (\frac{x - 1}{3})