What is the derivative of 2sqrt(x+1) ?

The derivative of 2sqrt(x+1) is 1/(sqrt(x+1))

What is the first derivative of 2sqrt(x+1) ?

The first derivative of 2sqrt(x+1) is 1/(sqrt(x+1))

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\frac{d}{d x} (2 x + 1)

\frac{1}{x + 1}

Solution steps

\frac{d}{d x} (2 x + 1)

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 2 \frac{d}{d x} (x + 1)

Apply the chain rule:

\frac{1}{2 x + 1} \frac{d}{d x} (x + 1)

= \frac{1}{2 x + 1} \frac{d}{d x} (x + 1)

\frac{d}{d x} (x + 1) = 1

= 2 \cdot \frac{1}{2 x + 1} \cdot 1

Simplify

2 \cdot \frac{1}{2 x + 1} \cdot 1 : \frac{1}{x + 1}

= \frac{1}{x + 1}

\int_{- \infty}^{0} e^{8 x} d x

\frac{\partial}{\partial y} (\frac{x}{( x + y )})

\int x^{2} \cdot sin (n x) d x

\frac{d y}{d x} = y + 5 x

\frac{\partial}{\partial y} (4 x z sin (y))

What is the derivative of 2sqrt(x+1) ?
The derivative of 2sqrt(x+1) is 1/(sqrt(x+1))
What is the first derivative of 2sqrt(x+1) ?
The first derivative of 2sqrt(x+1) is 1/(sqrt(x+1))