What is (\partial)/(\partial y)(4xzsin(y)) ?

The answer to (\partial)/(\partial y)(4xzsin(y)) is 4xzcos(y)

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(\partial)/(\partial y)(4xzsin(y))

\frac{\partial}{\partial y} (4 x z sin (y))

4 x z cos (y)

Solution steps

\frac{\partial}{\partial y} (4 x z sin (y))

Treat

x, z

as constants

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 4 x z \frac{\partial}{\partial y} (sin (y))

Apply the common derivative:

\frac{\partial}{\partial y} (sin (y)) = cos (y)

= 4 x z cos (y)

\frac{d}{d x} (x (x + 13))

(1 + ln (x) + \frac{y}{x}) d x = (9 - ln (x)) d y

\frac{\partial}{\partial x} (x^{8} e^{x y})

\int 4 x^{2} e^{- 2 x} d x

\frac{\partial}{\partial x} (x^{- 2} \cdot \frac{y}{x ^{3}})

What is (\partial)/(\partial y)(4xzsin(y)) ?
The answer to (\partial)/(\partial y)(4xzsin(y)) is 4xzcos(y)