What is the derivative of sqrt(r^2-19x^2) ?

The derivative of sqrt(r^2-19x^2) is (r\frac{dr)/(dx)-19x}{sqrt(r^2-19x^2)}

What is the first derivative of sqrt(r^2-19x^2) ?

The first derivative of sqrt(r^2-19x^2) is (r\frac{dr)/(dx)-19x}{sqrt(r^2-19x^2)}

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\frac{d}{d x} (r^{2} - 19 x^{2})

\frac{r \frac{d r}{d x} - 19 x}{r ^{2} - 19 x ^{2}}

Solution steps

\frac{d}{d x} (r^{2} - 19 x^{2})

Apply the chain rule:

\frac{1}{2 r ^{2} - 19 x ^{2}} \frac{d}{d x} (r^{2} - 19 x^{2})

= \frac{1}{2 r ^{2} - 19 x ^{2}} \frac{d}{d x} (r^{2} - 19 x^{2})

\frac{d}{d x} (r^{2} - 19 x^{2}) = 2 r \frac{d r}{d x} - 38 x

= \frac{1}{2 r ^{2} - 19 x ^{2}} (2 r \frac{d r}{d x} - 38 x)

Simplify

\frac{1}{2 r ^{2} - 19 x ^{2}} (2 r \frac{d r}{d x} - 38 x) : \frac{r \frac{d r}{d x} - 19 x}{r ^{2} - 19 x ^{2}}

= \frac{r \frac{d r}{d x} - 19 x}{r ^{2} - 19 x ^{2}}

x \to 3 lim (x^{2} + 3 x)

x \to 2 lim ((x^{2} - 3) e^{x})

f (x) = x + \frac{3}{x ^{2}}

\frac{d}{d x} (2 x sin (π x))

y^{^{''}} - (3 + π) y^{^{'}} + 3 π \cdot y = sin (\frac{π}{2})

What is the derivative of sqrt(r^2-19x^2) ?
The derivative of sqrt(r^2-19x^2) is (r\frac{dr)/(dx)-19x}{sqrt(r^2-19x^2)}
What is the first derivative of sqrt(r^2-19x^2) ?
The first derivative of sqrt(r^2-19x^2) is (r\frac{dr)/(dx)-19x}{sqrt(r^2-19x^2)}