What is the solution for (dy)/(dx)= 1/(x+e^y) ?

The solution for (dy)/(dx)= 1/(x+e^y) is y=\W(x/(e^{c_{1)}})+c_{1}

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(dy)/(dx)= 1/(x+e^y)

\frac{d y}{d x} = \frac{1}{x + e ^{y}}

y = W (\frac{x}{e ^{c_{1}}}) + c_{1}

Solution steps

\frac{d y}{d x} = \frac{1}{x + e ^{y}}

Solve exact ODE:

y = W (\frac{x}{e ^{c_{1}}}) + c_{1}

y = W (\frac{x}{e ^{c_{1}}}) + c_{1}

\frac{d}{d x} \frac{5 x}{ln ( ( 4 x - 1 ) ^{2} )}

x \to \infty lim (g (x))

5 x^{2} - 3 x - 5

f (x) = e^{x^{7}}, (- 1, \frac{1}{e})

\frac{d}{d x} (\frac{x ^{2} cos ( e ^{x} )}{( 2 x + 1 ) ^{3}})

What is the solution for (dy)/(dx)= 1/(x+e^y) ?
The solution for (dy)/(dx)= 1/(x+e^y) is y=\W(x/(e^{c_{1)}})+c_{1}