What is the derivative of 8sin^3(t) ?

The derivative of 8sin^3(t) is 24sin^2(t)cos(t)

What is the first derivative of 8sin^3(t) ?

The first derivative of 8sin^3(t) is 24sin^2(t)cos(t)

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derivative of

8 sin^{3} (t)

24 sin^{2} (t) cos (t)

Solution steps

\frac{d}{d t} (8 sin^{3} (t))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 8 \frac{d}{d t} (sin^{3} (t))

Apply the chain rule:

3 (sin (t))^{2} \frac{d}{d t} (sin (t))

= 3 (sin (t))^{2} \frac{d}{d t} (sin (t))

\frac{d}{d t} (sin (t)) = cos (t)

= 8 \cdot 3 (sin (t))^{2} cos (t)

Simplify

= 24 sin^{2} (t) cos (t)

\int \frac{sec ( u )}{tan ( u )} d u

y = x^{3} - 3 x

\frac{d}{d x} (\frac{1 + sin ( x )}{1 + cos ( x )})

(2 r a^{r x} + n)^{p}

x \to 0 + lim (x^{x^{x}})

What is the derivative of 8sin^3(t) ?
The derivative of 8sin^3(t) is 24sin^2(t)cos(t)
What is the first derivative of 8sin^3(t) ?
The first derivative of 8sin^3(t) is 24sin^2(t)cos(t)