What is the tangent of f(x)= 7/(x^2)-6x^2,\at x=5 ?

The tangent of f(x)= 7/(x^2)-6x^2,\at x=5 is y=-7514/125 x+3771/25

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

tangent of f(x)= 7/(x^2)-6x^2,\at x=5

tangent of

f (x) = \frac{7}{x ^{2}} - 6 x^{2}, at x = 5

y = - \frac{7514}{125} x + \frac{3771}{25}

Solution steps

Find the tangent point:

(5, - \frac{3743}{25})

Find the slope of

f (x) = \frac{7}{x ^{2}} - 6 x^{2} : \frac{df ( x )}{d x} = - \frac{14}{x ^{3}} - 12 x

Compute the slope of

f (x) = \frac{7}{x ^{2}} - 6 x^{2}

x = 5 : m = - \frac{7514}{125}

Find the line with slope m=

- \frac{7514}{125}

and passing through

(5, - \frac{3743}{25}) : y = - \frac{7514}{125} x + \frac{3771}{25}

y = - \frac{7514}{125} x + \frac{3771}{25}

\frac{d}{d x} (2 x^{2} + 1)

\int \frac{( 1 - x )}{e ^{x}} k d x

x \to 0 lim (+ (ln (x)))

y^{^{''}} - 8 y^{^{'}} - 15 y = 0

\frac{2 x}{5}

What is the tangent of f(x)= 7/(x^2)-6x^2,\at x=5 ?
The tangent of f(x)= 7/(x^2)-6x^2,\at x=5 is y=-7514/125 x+3771/25