What is the derivative of (x+1/(\sqrt[3]{x})^2) ?

The derivative of (x+1/(\sqrt[3]{x})^2) is 2(x+1/(\sqrt[3]{x)})(1-1/(3x^{4/3)})

What is the first derivative of (x+1/(\sqrt[3]{x})^2) ?

The first derivative of (x+1/(\sqrt[3]{x})^2) is 2(x+1/(\sqrt[3]{x)})(1-1/(3x^{4/3)})

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Solution steps

Apply the chain rule:

a^{2} x^{2} + b^{2}

y = (\frac{( x ^{2} + 8 )}{x ^{2} - 8})

3 t^{2} + 13 t + 13

e^{\frac{( x ^{5} )}{5}}

\frac{1}{( 1 - t ^{2} ) ^{\frac{1}{2}}}

What is the derivative of (x+1/(\sqrt[3]{x})^2) ?
The derivative of (x+1/(\sqrt[3]{x})^2) is 2(x+1/(\sqrt[3]{x)})(1-1/(3x^{4/3)})
What is the first derivative of (x+1/(\sqrt[3]{x})^2) ?
The first derivative of (x+1/(\sqrt[3]{x})^2) is 2(x+1/(\sqrt[3]{x)})(1-1/(3x^{4/3)})