What is the integral from 0 to 1 of (89)/(x^5) ?

The integral from 0 to 1 of (89)/(x^5) is diverges

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integral from 0 to 1 of (89)/(x^5)

\int_{0}^{1} \frac{89}{x ^{5}} d x

diverges

Solution steps

\int_{0}^{1} \frac{89}{x ^{5}} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 89 \cdot \int_{0}^{1} \frac{1}{x ^{5}} d x

Apply the Power Rule

: [- \frac{1}{4 x ^{4}}]_{0}^{1}

= 89 [- \frac{1}{4 x ^{4}}]_{0}^{1}

Compute the boundaries:

diverges

= diverges

x y^{^{'}} + 2 y = x^{3} - 4

\int_{4}^{\infty} 7 e^{- \frac{x}{2}} d x

\frac{d}{d x} (4^{- x^{2}})

\frac{d}{d x} (4 cos (2 x))

\frac{d}{d x} (x^{2} (x - y)^{2}) = x^{2} - y^{2}

What is the integral from 0 to 1 of (89)/(x^5) ?
The integral from 0 to 1 of (89)/(x^5) is diverges