What is the d/(dθ)(tan(θ/2)) ?

The d/(dθ)(tan(θ/2)) is sec^2(θ/2) 1/2

What is the first d/(dθ)(tan(θ/2)) ?

The first d/(dθ)(tan(θ/2)) is sec^2(θ/2) 1/2

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\frac{d}{d θ} (tan (\frac{θ}{2}))

sec^{2} (\frac{θ}{2}) \frac{1}{2}

Solution steps

\frac{d}{d θ} (tan (\frac{θ}{2}))

Apply the chain rule:

sec^{2} (\frac{θ}{2}) \frac{d}{d θ} (\frac{θ}{2})

= sec^{2} (\frac{θ}{2}) \frac{d}{d θ} (\frac{θ}{2})

\frac{d}{d θ} (\frac{θ}{2}) = \frac{1}{2}

= sec^{2} (\frac{θ}{2}) \frac{1}{2}

\int (x^{2} - 2 x + 5) d x

\int_{- 8}^{8} (e^{x} - e^{- x})^{2} d x

\int_{0}^{2} x + 1 d x

\frac{\partial}{\partial x} (4 x^{\frac{2}{3}} y^{\frac{1}{3}})

t (e^{t} + e^{2 t})^{2}

What is the d/(dθ)(tan(θ/2)) ?
The d/(dθ)(tan(θ/2)) is sec^2(θ/2) 1/2
What is the first d/(dθ)(tan(θ/2)) ?
The first d/(dθ)(tan(θ/2)) is sec^2(θ/2) 1/2