What is (\partial)/(\partial x)(4x(5+y)^{-1}) ?

The answer to (\partial)/(\partial x)(4x(5+y)^{-1}) is 4/(5+y)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(\partial)/(\partial x)(4x(5+y)^{-1})

\frac{\partial}{\partial x} (4 x (5 + y)^{- 1})

\frac{4}{5 + y}

Solution steps

\frac{\partial}{\partial x} (4 x (5 + y)^{- 1})

Treat

y

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 4 (5 + y)^{- 1} \frac{\partial}{\partial x} (x)

Apply the common derivative:

\frac{\partial}{\partial x} (x) = 1

= 4 (5 + y)^{- 1} \cdot 1

Simplify

4 (5 + y)^{- 1} \cdot 1 : \frac{4}{5 + y}

= \frac{4}{5 + y}

y^{^{'}} + 2 x y = x^{3}

\frac{d}{d x} (\frac{2 x - y}{x + 2 y})

\frac{d}{d x} (x (x^{2} - 4))

f (x) = x^{3} + 2 x, at x = 0

\frac{\partial}{\partial x} (8 x y + 2 x^{4} + 2 y^{4})

What is (\partial)/(\partial x)(4x(5+y)^{-1}) ?
The answer to (\partial)/(\partial x)(4x(5+y)^{-1}) is 4/(5+y)