What is the derivative of 1/6 \sqrt[5]{(6-5x^2^7}) ?

The derivative of 1/6 \sqrt[5]{(6-5x^2^7}) is -(7x(-5x^2+6)^{2/5})/3

What is the first derivative of 1/6 \sqrt[5]{(6-5x^2^7}) ?

The first derivative of 1/6 \sqrt[5]{(6-5x^2^7}) is -(7x(-5x^2+6)^{2/5})/3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

- \frac{7 x ( - 5 x ^{2} + 6 ) ^{\frac{2}{5}}}{3}

Solution steps

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

Apply the chain rule:

\frac{1}{5 ( ( 6 - 5 x ^{2} ) ^{7} ) ^{\frac{4}{5}}} \frac{d}{d x} ((6 - 5 x^{2})^{7})

= \frac{1}{5 ( ( 6 - 5 x ^{2} ) ^{7} ) ^{\frac{4}{5}}} \frac{d}{d x} ((6 - 5 x^{2})^{7})

\frac{d}{d x} ((6 - 5 x^{2})^{7}) = - 70 x (6 - 5 x^{2})^{6}

= \frac{1}{6} \cdot \frac{1}{5 ( ( 6 - 5 x ^{2} ) ^{7} ) ^{\frac{4}{5}}} (- 70 x (6 - 5 x^{2})^{6})

Simplify

\frac{1}{6} \cdot \frac{1}{5 ( ( 6 - 5 x ^{2} ) ^{7} ) ^{\frac{4}{5}}} (- 70 x (6 - 5 x^{2})^{6}) : - \frac{7 x ( - 5 x ^{2} + 6 ) ^{\frac{2}{5}}}{3}

= - \frac{7 x ( - 5 x ^{2} + 6 ) ^{\frac{2}{5}}}{3}

\frac{\partial}{\partial x} (4 x y - 2 x^{2} y)

\int x e^{- \frac{1}{10} x^{2}} d x

\frac{d ^{3}}{d x ^{3}} ((1 + x)^{3})

\frac{\partial}{\partial x} (2 x y^{3} + 2)

What is the derivative of 1/6 \sqrt[5]{(6-5x^2^7}) ?
The derivative of 1/6 \sqrt[5]{(6-5x^2^7}) is -(7x(-5x^2+6)^{2/5})/3
What is the first derivative of 1/6 \sqrt[5]{(6-5x^2^7}) ?
The first derivative of 1/6 \sqrt[5]{(6-5x^2^7}) is -(7x(-5x^2+6)^{2/5})/3