What is (\partial)/(\partial x)(4xy-2x^2y) ?

The answer to (\partial)/(\partial x)(4xy-2x^2y) is 4y-4yx

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(\partial)/(\partial x)(4xy-2x^2y)

\frac{\partial}{\partial x} (4 x y - 2 x^{2} y)

4 y - 4 y x

Solution steps

\frac{\partial}{\partial x} (4 x y - 2 x^{2} y)

Treat

y

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (4 x y) - \frac{\partial}{\partial x} (2 x^{2} y)

\frac{\partial}{\partial x} (4 x y) = 4 y

\frac{\partial}{\partial x} (2 x^{2} y) = 4 y x

= 4 y - 4 y x

\int x e^{- \frac{1}{10} x^{2}} d x

\frac{d ^{3}}{d x ^{3}} ((1 + x)^{3})

\frac{\partial}{\partial x} (2 x y^{3} + 2)

y^{^{'}} - (\frac{3}{t}) \cdot y = 2 t^{3} \cdot e^{(2 t)}, y (1) = 0

\frac{d}{d x} (ln (1 - e^{- x}))

What is (\partial)/(\partial x)(4xy-2x^2y) ?
The answer to (\partial)/(\partial x)(4xy-2x^2y) is 4y-4yx