What is the solution for y^'-(3/t)*y=2t^3*e^{(2t)},y(1)=0 ?

The solution for y^'-(3/t)*y=2t^3*e^{(2t)},y(1)=0 is y=e^{2t}t^3-e^2t^3

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y^'-(3/t)y=2t^3e^{(2t)},y(1)=0

y^{^{'}} - (\frac{3}{t}) \cdot y = 2 t^{3} \cdot e^{(2 t)}, y (1) = 0

y = e^{2 t} t^{3} - e^{2} t^{3}

Solution steps

y^{'} (t) - (\frac{3}{t}) \cdot y = 2 t^{3} \cdot e^{(2 t)}

Solve linear ODE:

y = e^{2 t} t^{3} - e^{2} t^{3}

y = e^{2 t} t^{3} - e^{2} t^{3}

\frac{d}{d x} (ln (1 - e^{- x}))

n = 1 \sum \infty \frac{1}{2 ^{n} - 5}

\frac{d y}{d t} + 0.7 t y = 7 t

y = 5 x^{2} + 2 x y - 3 y^{2} + 3, (2, 1)

\frac{\partial}{\partial x} (1 - 9 x^{2} - 6 y^{2})

What is the solution for y^'-(3/t)*y=2t^3*e^{(2t)},y(1)=0 ?
The solution for y^'-(3/t)*y=2t^3*e^{(2t)},y(1)=0 is y=e^{2t}t^3-e^2t^3