What is the solution for (dy)/(dt)+0.7ty=7t ?

The solution for (dy)/(dt)+0.7ty=7t is y=(e^{-0.35t^2+c_{1}})/(0.7)+7/(0.7)

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(dy)/(dt)+0.7ty=7t

\frac{d y}{d t} + 0.7 t y = 7 t

y = \frac{e ^{- 0.35 t^{2} + c_{1}}}{0.7} + \frac{7}{0.7}

Solution steps

\frac{d y}{d t} + 0.7 t y = 7 t

Solve separable ODE:

y = \frac{e ^{- 0.35 t^{2} + c_{1}}}{0.7} + \frac{7}{0.7}

y = \frac{e ^{- 0.35 t^{2} + c_{1}}}{0.7} + \frac{7}{0.7}

y = 5 x^{2} + 2 x y - 3 y^{2} + 3, (2, 1)

\frac{\partial}{\partial x} (1 - 9 x^{2} - 6 y^{2})

f (x) = (x + 2) \cdot - x

\frac{d y}{d x} = \frac{2 y}{x} - x^{2} y^{2}

y^{^{''}} + 3 y^{^{'}} + 2 y = \frac{1}{3 + e ^{x}}

What is the solution for (dy)/(dt)+0.7ty=7t ?
The solution for (dy)/(dt)+0.7ty=7t is y=(e^{-0.35t^2+c_{1}})/(0.7)+7/(0.7)