What is the solution for (dy}{dx}=\frac{2y)/x-x^2y^2 ?

The solution for (dy}{dx}=\frac{2y)/x-x^2y^2 is y=(5x^2)/(x^5+c_{1)}

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(dy}{dx}=\frac{2y)/x-x^2y^2

\frac{d y}{d x} = \frac{2 y}{x} - x^{2} y^{2}

y = \frac{5 x ^{2}}{x ^{5} + c _{1}}

Solution steps

\frac{d y}{d x} = \frac{2 y}{x} - x^{2} y^{2}

Solve Bernoulli ODE:

y = \frac{5 x ^{2}}{x ^{5} + c _{1}}

y = \frac{5 x ^{2}}{x ^{5} + c _{1}}

y^{^{''}} + 3 y^{^{'}} + 2 y = \frac{1}{3 + e ^{x}}

d y - (y - 6)^{2} d x = 0

x \to 1 lim (2 x^{2} - x)

x \to - 1 lim (\frac{3 - 4 x}{x})

What is the solution for (dy}{dx}=\frac{2y)/x-x^2y^2 ?
The solution for (dy}{dx}=\frac{2y)/x-x^2y^2 is y=(5x^2)/(x^5+c_{1)}