What is the derivative of (4x+1^2) ?

The derivative of (4x+1^2) is 8(4x+1)

What is the first derivative of (4x+1^2) ?

The first derivative of (4x+1^2) is 8(4x+1)

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\frac{d}{d x} ((4 x + 1)^{2})

8 (4 x + 1)

Solution steps

\frac{d}{d x} ((4 x + 1)^{2})

Apply the chain rule:

2 (4 x + 1) \frac{d}{d x} (4 x + 1)

= 2 (4 x + 1) \frac{d}{d x} (4 x + 1)

\frac{d}{d x} (4 x + 1) = 4

= 2 (4 x + 1) \cdot 4

Simplify

= 8 (4 x + 1)

\frac{d}{d x} (\frac{1}{( 1 - 2 x )})

e^{4 t}

\frac{d}{d x} (2 x^{4} + x^{3} + 5 x^{2} - 3 x + 8)

\frac{d}{d x} (x^{2} \cdot e^{- 3 x})

(e^{t} x + 1) d t + (e^{t} - 1) d x = 0, x (1) = 1

What is the derivative of (4x+1^2) ?
The derivative of (4x+1^2) is 8(4x+1)
What is the first derivative of (4x+1^2) ?
The first derivative of (4x+1^2) is 8(4x+1)