What is the solution for (x^2+1)y^'+9x(y-1)=0,y(0)=4 ?

The solution for (x^2+1)y^'+9x(y-1)=0,y(0)=4 is y= 3/((x^2+1)^{9/2)}+1

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(x^2+1)y^'+9x(y-1)=0,y(0)=4

(x^{2} + 1) y^{^{'}} + 9 x (y - 1) = 0, y (0) = 4

y = \frac{3}{( x ^{2} + 1 ) ^{\frac{9}{2}}} + 1

Solution steps

(x^{2} + 1) y^{'} (x) + 9 x (y - 1) = 0

Solve separable ODE:

y = \frac{3}{( x ^{2} + 1 ) ^{\frac{9}{2}}} + 1

y = \frac{3}{( x ^{2} + 1 ) ^{\frac{9}{2}}} + 1

\int u^{2} u^{3} + 2 d u

sin (x^{7})

y + 2 t^{2} + y^{^{'}} t ln (t) = 0

\int \frac{x + 8}{x ^{2} + 16} d x

\frac{\partial}{\partial y} (3 x^{2} - 2 x y + 2)

What is the solution for (x^2+1)y^'+9x(y-1)=0,y(0)=4 ?
The solution for (x^2+1)y^'+9x(y-1)=0,y(0)=4 is y= 3/((x^2+1)^{9/2)}+1