What is area f(x)=x^2+4x,g(x)=x+10 ?

The answer to area f(x)=x^2+4x,g(x)=x+10 is 343/6

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area f(x)=x^2+4x,g(x)=x+10

area

f (x) = x^{2} + 4 x, g (x) = x + 10

\frac{343}{6}

Decimal Notation

57.16666 \dots

Solution steps

Apply the area formula:

\int_{- 5}^{2} x^{2} + 4 x - (x + 10) d x

Solve

\int_{- 5}^{2} x^{2} + 4 x - (x + 10) d x : \frac{343}{6}

The area is:

= \frac{343}{6}

\frac{3}{s + 5}

f (x) = ln (e^{4})

\int \frac{( 6 x ^{3} + 6 x )}{x ^{2} + 1} d x

\frac{d y}{d x} + 3 y = 6

\int e^{- x} (x - 1) d x

What is area f(x)=x^2+4x,g(x)=x+10 ?
The answer to area f(x)=x^2+4x,g(x)=x+10 is 343/6