What is the limit as x approaches-2 of (z+2)/(x^2+4) ?

The limit as x approaches-2 of (z+2)/(x^2+4) is 1/8 (z+2)

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limit as x approaches-2 of (z+2)/(x^2+4)

x \to - 2 lim (\frac{z + 2}{x ^{2} + 4})

\frac{1}{8} (z + 2)

Solution steps

x \to - 2 lim (\frac{z + 2}{x ^{2} + 4})

Plug in the value

x = - 2

= \frac{z + 2}{( - 2 ) ^{2} + 4}

Simplify

\frac{z + 2}{( - 2 ) ^{2} + 4} : \frac{1}{8} (z + 2)

= \frac{1}{8} (z + 2)

\int 3 sec^{2} (x) tan (x) d x

x \to 3 lim (I n (x^{2} - 9))

\int e^{a x} sin (b) x d x

\frac{\partial}{\partial y} (y arcsin (x y))

f (x) = 3 - x + x^{2}

What is the limit as x approaches-2 of (z+2)/(x^2+4) ?
The limit as x approaches-2 of (z+2)/(x^2+4) is 1/8 (z+2)