What is the derivative of f(x)=3-x+x^2 ?

The derivative of f(x)=3-x+x^2 is 2x-1

What is the first derivative of f(x)=3-x+x^2 ?

The first derivative of f(x)=3-x+x^2 is 2x-1

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derivative of

f (x) = 3 - x + x^{2}

2 x - 1

Solution steps

\frac{d}{d x} (3 - x + x^{2})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (3) - \frac{d x}{d x} + \frac{d}{d x} (x^{2})

\frac{d}{d x} (3) = 0

\frac{d x}{d x} = 1

\frac{d}{d x} (x^{2}) = 2 x

= 0 - 1 + 2 x

Simplify

= 2 x - 1

\frac{x}{x + 5}

\frac{d}{d x} (- cos (x) + sin (x))

f (x) = (3 x^{2} + 1)^{4}

3 + 5 x^{2} - 2 x^{3}

\int \frac{x ^{2} - 4}{x ^{2}} d x

What is the derivative of f(x)=3-x+x^2 ?
The derivative of f(x)=3-x+x^2 is 2x-1
What is the first derivative of f(x)=3-x+x^2 ?
The first derivative of f(x)=3-x+x^2 is 2x-1