What is the derivative of 3x^3-4 ?

The derivative of 3x^3-4 is 9x^2

What is the first derivative of 3x^3-4 ?

The first derivative of 3x^3-4 is 9x^2

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\frac{d}{d x} (3 x^{3} - 4)

9 x^{2}

Solution steps

\frac{d}{d x} (3 x^{3} - 4)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (3 x^{3}) - \frac{d}{d x} (4)

\frac{d}{d x} (3 x^{3}) = 9 x^{2}

\frac{d}{d x} (4) = 0

= 9 x^{2} - 0

Simplify

= 9 x^{2}

8 e^{2 x}

\int e^{- x} - e^{x} d x

y^{^{''}} + 11 y = 0

x^{2} = 2 y

y = 9 x, y = \frac{3}{7} x, y = 52 - x^{2}