What is the integral of e^{6x+4} ?

The integral of e^{6x+4} is 1/6 e^{6x+4}+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral of e^{6x+4}

\int e^{6 x + 4} d x

\frac{1}{6} e^{6 x + 4} + C

Solution steps

\int e^{6 x + 4} d x

Apply u-substitution

: \int e^{u} \frac{1}{6} d u

= \int e^{u} \frac{1}{6} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{6} \cdot \int e^{u} d u

Use the common integral:

\int e^{u} d u = e^{u}

= \frac{1}{6} e^{u}

Substitute back

u = 6 x + 4

= \frac{1}{6} e^{6 x + 4}

Add a constant to the solution

= \frac{1}{6} e^{6 x + 4} + C

\int_{0}^{6} x^{3} e^{x} d x

n = 1 \sum \infty \frac{1}{n ^{2} - 1}

\int_{0}^{1} x^{4} e^{6 x} d x

\int - t z d t

e^{2 x} y^{^{'}} - 2 e^{2 x} y = 3 e^{4 x}